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If f(x)=64x^3+1/x^3 and alpha,beta are t...

If `f(x)=64x^3+1/x^3` and `alpha,beta` are the roots of `4x+1/x=3`. Then,`f(alpha)=f(beta)`

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Given,
`f(x) = 64x^3 + 1/x^3`
`=(4x+1/x)^3 -3(4x)(1/x) (4x+1/x)`
Since, `4x+ 1/x = 3 `
...
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