The difference between the two acute angles of a right angled triangle is `(pi)/9` radians. Express the angles in degrees.

Explanation

`pi` radians `=180^{circ}`


`frac{pi}{9}` radian `=frac{180}{pi} times frac{pi}{9}=20^{circ}`


Let the two acute angles of the -angled triangle be `x` and `y(x>y)`


Then `x+y=90^{circ}`


and `x-y=20^{circ}`


Solving (i) and (ii) we get


`2 x=110^{circ}`


`Rightarrow x=55^{circ} `


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