Find the length which at a distance of 5280 m will subtend an angle of 1' at the eye.

Explanation

Let, `angle {AOB}=theta=1^{prime}`


`A B= {arc} A B=1`


`{OA}={OB}={r}=5280 {~m}`


`because`` 1^{circ}=60^{prime}`


`Rightarrow quad 1^{prime}=(frac{1}{60})^{circ}=(frac{1}{60} times frac{pi}{180})^{circ}`


`[because quad 1^{circ}=(frac{pi}{180})^{c}]`


Now,


We know that


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