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If the arcs of the same lengths m two circles subtend angles `65o` and `110o` at the centre, find the ratio of their radii.

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Let, r1 and r2 be the radii of the two circles.
Given, `θ1=65^0⇒π/180×65^0=13π/36`radian and
`θ2=110^0⇒π/180×110^0=22/26 `radian
Let, `l` be the length of each of the arc. Then,
`l=r1 θ1=r2 θ2`
so, `13pi/36 *r1=22pi/36*r2`
...
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