If `sintheta=(a^2-b^2)/(a^2+b^2),` find the value of `t a ntheta,\ s e ctheta\ a n d\ cosectheta`

Explanation

Let's assume a triangle right angled at B such that
Perpendicular `= a^
2
−b ^
2`
and, Hypotenuse` = a ^
2+b^ 2`
. and ∠BAC=θ

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