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Find the values of the following trigono...

Find the values of the following trigonometric ratio: `cos570^@`

Text Solution

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`cos 570^{circ}=cos (3 pi+frac{pi}{6})`
`=cos (2 pi+(pi+frac{pi}{6}))`
`=cos (pi+frac{pi}{6})`
`{ cos (2 pi+theta)=cos theta`, as cosine is periodoc with period `2 pi] `
`=-cos frac{pi}{6}`
`{therefore cos (pi+theta)=-cos theta] `
`=frac{-3}{2}`
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