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Find `x` from the following equation: `cos e c(90^@+theta)+x costhetacot(90^@+theta)=sin(90^@+theta)`

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Given equation is ,
`csc(90+theta)x cos theta cot(90+theta) = sin (90+theta)`
We know that ,
`cosec(90+theta)=sec theta`
`cot (90+theta)=-tan theta`
`sin (90+theta)=cos theta`
Put these values in the given equation, we get
`Rightarrow sec theta+x cos theta(-tan theta)=cos theta `
...
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