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If sin x=cos^2x ,\ then write the value...

If `sin x=cos^2x ,\ ` then write the value of `cos^2x\ (1+cos^2x)dot`

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Given that:-`sinx=cos^2x`
Thus `sinx=1-sin^2x`
`=> sin^2x+sinx=1`---(1)
We need to find value of `cos^2x(1+cos^2x)`
...
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