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If s e ctheta+t a ntheta=k ,\ costheta= ...

If `s e ctheta+t a ntheta=k ,\ costheta=`
a.`(k^2+1)/(2k)` b. `(2k)/(k^2+1)` c. `k/(k^2+1)` d. `k/(k^2-1)`

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To solve the problem, we start with the given equation: 1. **Given**: \( \sec \theta + \tan \theta = k \) 2. **Using the identity**: We know that: \[ \sec^2 \theta - \tan^2 \theta = 1 \] ...
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RD SHARMA-TRIGONOMETRIC FUNCTIONS-Solved Examples And Exercises
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