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The linkage map of X-chromosome of fruit...

The linkage map of X-chromosome of fruit fly has 66 units with yellow body gene Y at one end and bobbed hair B gene at he other end. The recombination frequency between these two genes Y and B should be

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The linkage map of X- chromosomes of fruitfly has 66 units with yellow body gene (y) at one end and bobbed hair (b) gene at the other end. The recombination frequency between these two genes (y and b) should be :

the linkage map of X -chroosomes of fruitfly has 66 units with yellow body gene (y) at one end and bobbed hair (b) gene at the other end the recomnation frequency between these two genes (y and b) should be :

the linkage map of X -chroosomes of fruitfly has 66 units with yellow body gene (y) at one end and bobbed hair (b) gene at the other end the recomnation frequency between these two genes (y and b) should be :

The linkage map of X - chrommosomes of fruitfly has 66 units , with yellow body gene (y) at one end and bobbed hair (b) gene at the other end . The recombination frequency between these two genes (y and b) should be

The map distance in a certain organism between genes A and B is 8 units, between B and C is 4 units and between C and D is 12 units. Which one of these gene pairs will show more recombination frequency? Give reason in just one single sentence in support of your answer.

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If (a, b) be an end of a diagonal of a square and the other diagonal has the equation x-y=a , then another vertex of the square can be

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