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If sinx=(sqrt(5))/3a n d\ x lies in IInd...

If `sinx=(sqrt(5))/3a n d\ x` lies in IInd quadrant, find the values of `cosx/2,sinx/2a n dtanx/2dot`

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Verified by Experts

Given, ` x` lies in `II` nd quadrant

the range is
`=> pi/2 lt x lt pi`
` =>pi/4 lt x/2 lt pi/2`
which means `x/2` lies in first quadrant
Now, `sin x=sqrt(5)/3=p/h`
...
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