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If 2\ t a nalpha=3t a nbeta, prove that...

If `2\ t a nalpha=3t a nbeta,` prove that `tan(alpha-beta)=(sin2beta)/(5-cos2beta)`

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Given,
`=>2tanalpha=3tanbeta,` and
`=>tanalpha=3/2tanbeta,` and
Now, `=>tan(alpha-beta)=(tanalpha−tanbeta​)/(1+tanalphatanbeta)`
...
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