`8.sin(x/8).cos(x/2).cos(x/4).cos(x/8)=`

Explanation

By rearrange the following formula, we get

`2 sin frac{x}{8} cos frac{x}{8}. 4 cos frac{x}{2} cos frac{x}{4}`

We know that, `sin2x=2sinx cosx`

`=2 sin frac{x}{8} cos frac{x}{8}. 4 cos frac{x}{2} cos frac{x}{4}`

`=2 sin frac{x}{4} cos frac{x}{4}. 2cos frac{x}{2}`

`=sin frac{x}{2}. 2 cos frac{x}{2}`

`=sin(x)`