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In a Delta A B C ,\ if\ a=2,\ b=3\ a n d...

In a `Delta A B C ,\ if\ a=2,\ b=3\ a n d\ sin A=2/3` then find `/_B`

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In `Delta ABC`, `a=2, b=3` and `sin A=frac{2}{3}`
By applying sin law,
`frac{a}{sin A}=frac{b}{sin B}frac{c}{sin C}`
`frac{2}{frac{2}{3}}=frac{3}{sin B}=>sin B=1=>B=frac{pi}{2}`
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