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In any DeltaA B C prove that acosA+bcos...

In any ` DeltaA B C` prove that `acosA+bcosB+c cosC=(8Delta^2)/(a b c)dot`

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From the cosine rule:
`cos (A)=frac{b^{2}+c^{2}-a^{2}}{2 b c}`
So
`a cos (A)+b cos (B)+c cos (C) =a frac{b^{2}+c^{2}-a^{2}}{2 b c}+b frac{a^{2}+c^{2}-b^{2}}{2 a c}+c frac{a^{2}+b^{2}-c^{2}}{2 a b} `
`=a^{2} frac{b^{2}+c^{2}-a^{2}}{2 a b c}+b^{2} frac{a^{2}+c^{2}-b^{2}}{2 a b c}+c^{2} frac{a^{2}+b^{2}-c^{2}}{2 a b c}`
`=frac{a^{2} b^{2}+a^{2} c^{2}-a^{4}+a^{2} b^{2}+b^{2} c^{2}-b^{4}+a^{2} c^{2}+b^{2} c^{2}-c^{4}}{2 a b c} `
`=frac{-(a-b-c)(a+b-c)(a+c-b)(a+b+c)}{2 a b c} `
`=frac{(b+c-a)(a+b-c)(a+c-b)(a+b+c)}{2 a b c} `
...
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