Two particles of same mass 'm' moving with velocities `vecv_1= vhati, and vecv_2 = (v/2)hati + (v/2)hatj`collide in-elastically. Find the loss in kinetic energy

Two particles of same mass m moving with velocities u_(1) and u_(2) collide perfectly inelastically. The loss of energy would be :

Two particles of same mass m moving with velocities u_(1) and u_(2) collide perfectly inelastically. The loss of energy would be :

Two particles of mass 2m and m moving with speed v and 2v respectively perpendicular to each other collides perfectly inelastically, then Loss in kinetic energy of the system

Two particles of equal mass m are moving with velocities vhati and v((hati+hatj)/(2)) respectively. If the particles collide completely inelastically, then the energy lost in the process is

Two particles of equal mass m are moving with velocities vhati and v((hati+hatj)/(2)) respectively. If the particles collide completely inelastically, then the energy lost in the process is

A particle of mass m moving with velocity 2v collides with another particle of mass 3m moving with velocity v in the same direction.If it is perfect inelastic collision,the loss of kinetic energy of the system is

Two objects having same mass 'm' are moving with velocities v and 2v. Find ratio of their kinetic energies.

Two objects having same mass 'm' are moving with velocities v and 2v. Find ratio of their kinetic energies.