Principal Solution of trigonometric equation: `tantheta=1/(sqrt(3))` are

Options

A. `pi/2, pi/3`
B. `pi/6, (5pi)/6`
C. `pi/6, (7pi)/6`
D. `(5pi)/6, (7pi)/6`

Answer

C

Explanation

It is given that` tan x = 1/(√3),` which is positive.


We know that tan is positive in the first and the third quadrants.


In the first quadrant,` x = π/6` as `tan π/6 = 1/(√3)`


In the third quadrant, `x = π + π/6 = 7π/6` as `tan 7π/6 = tan (π + π/6) = tan π/6 = 1/(√30`


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