Solve the following trigonometric equation: `\ t a n2theta=sqrt(3)`

Explanation

To solve the trigonometric equation \( \tan(2\theta) = \sqrt{3} \), we can follow these steps:

### Step 1: Identify the angle whose tangent is \( \sqrt{3} \)
We know that:
\[ \tan\left(\frac{\pi}{3}\right) = \sqrt{3} \]
This means that \( 2\theta \) can be equal to \( \frac{\pi}{3} \) plus any integer multiple of \( \pi \) (since the tangent function has a period of \( \pi \)).
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