Solve the following equation: `sin2theta+sin4theta+sin6theta=0`

Explanation

Given,`sin6theta+sin2theta+sin4theta=0`
⇒`sin6theta+sin2theta=−sin4theta`

⇒`2sin4thetacos2theta=−sin4theta`

As

`sin4theta=0⇒4theta=nπ∴theta=nπ/4`
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Or `cos2theta=−1/2​⇒2theta=2nπ±(2π)/3`

​∴`theta=nπ±π/3`
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