Find the general solutions of the following equation: `cosx=-(sqrt(3))/2`

Explanation

Given,`cos x = - (√3)/2`

We know that, `cos 150° = (−√3/2) = cos (5π)/6 `

∴` cos x = cos (5π)/6`

If` cos x = cos y` then` x = 2nπ ± y`, where n ∈ Z.

For above equation `y = (5π)/6` ∴ `x = 2nπ ± 5π / 6` ,where n ϵ Z