Find the general solutions of the following equation: `s e ctheta=sqrt(2)`

Explanation

The general solution of
`costheta=cosα ` is
`theta=2nπ±α,nϵZ`

Now,` sectheta=sqrt(2)`
​ ∴`costheta=1/sqrt(2)`
​

∴`costheta=cosπ/4`​

∴ the required general solution is

`theta=2nπ±(π/4)`​,nϵZ