Find the general solutions of the following equation: `sqrt(3)sectheta=2`

Explanation

The general solution of
`costheta=cosα ` is
`theta=2nπ±α,nϵZ`

Now,` sectheta=2/sqrt(3)`
​ ∴`costheta=sqrt(3)/2`
​

∴`costheta=cosπ/6`​

∴ the required general solution is

`theta=2nπ±(π/6)`​,nϵZ