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Find the general solutions of the following equation: `sqrt(3)sectheta=2`

Text Solution

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The general solution of
`costheta=cosα ` is `theta=2nπ±α,nϵZ`
Now,` sectheta=2/sqrt(3)` ​ ∴`costheta=sqrt(3)/2` ​
∴`costheta=cosπ/6`​
∴ the required general solution is
`theta=2nπ±(π/6)`​,nϵZ
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