Find the general solutions of the following equation: `sin2theta=\ (sqrt(3))/2`

Explanation

Given equation
`sin2theta=sqrt(3)/2`

`sin2theta=sin(π/3)`

If `sinx=siny`

then general formula is `x=nπ+(−1)^ny;`

using this we get ,
`2theta=nπ+(−1)^n(π/3)`

`theta=n(π/2)+(−1)^n(π/6)`

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