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Find the general solutions of the following equation: `cos3theta=1/2`

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Given,`cos 3x = 1/2`
We know that cos x and sec x have positive values in the 1st and 4th quadrant.
∴ `cos 3x = cos π/3`
If cos x = cos y then `x = 2nπ ± y,` where n ∈ Z
Clearly on comparing we have` y = π/3`
∴ `3x = 2nπ ± π/3`
⇒ `x = (2nπ)/3 ± (π)/9` ,where n ϵ Z
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