Solve the following equation: ` sin2theta-sin4theta+sin6theta=0`

Explanation

Given,`sin2theta+sin4theta+s in6theta=0`

=`sin2theta+sin6theta=-sin4theta`


=`2sin4thetacos2theta=−sin4theta`


`sin4theta=0⇒4theta=nπ∴theta=(nπ)/4`
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Or `cos2theta=(−1)/2​⇒2theta=2nπ±(2π)/3`
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