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Writhe the number of values of theta\ in...

Writhe the number of values of `theta\ in\ [0,2pi]` thast satisfy the equation `sin^2theta-costheta=1/4dot`

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Given,`sin^2theta-costheta=1/4`
=`sin^2theta-costheta=1/4`
=`1-cos^2theta-costheta=1/4`
=`cos^2theta+costheta=3/4`
=`4cos^2theta+4costheta=3`
=`4cos^2theta+4costheta-3=0`
=`(2costheta-1)(2costheta+3)=0`
So,`(2costheta-1)=0`
...
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