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If costheta+sqrt(3)sintheta=2, then thet...

If `costheta+sqrt(3)sintheta=2,` then `theta=` a.`pi//3` b. `2pi//3` c. `4pi//3` d. `5pi//3`

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Given,`costheta+sqrt(3)sintheta=2`
=`1/2costheta+sqrt(3)/2 sintheta=1`
=`sin30^0costheta+cos30^0sintheta=1`
⇒`sin(theta+30^0)=sin90^0`
⇒`theta+30^0=90^0`
or`theta=60^0`
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