The general solution of the equation `7cos^2theta+3sin^2theta=4` is `theta=2npi+-pi/6,\ n Z` b. `theta=2npi+-(2pi)/3,\ n Z` c. `theta=2npi+-pi/3,\ n Z` d. none of these

Explanation

To find the general solution of the equation \( 7 \cos^2 \theta + 3 \sin^2 \theta = 4 \), we can follow these steps:

### Step 1: Rewrite the equation
We start with the given equation:
\[ 7 \cos^2 \theta + 3 \sin^2 \theta = 4 \]
We know that \( \sin^2 \theta + \cos^2 \theta = 1 \). Therefore, we can express \( \sin^2 \theta \) in terms of \( \cos^2 \theta \):
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