The general value of `x` satisfying the equation satisfying the equation `sqrt(3)sin x+cos x=sqrt(3)` is given by `x=npi+(-1)^npi/4+pi/3,\ n Z` b. `x=npi+(-1)^npi/3+pi/6,\ n Z` c. `x=npi+-pi/6, n Z` d. `x=npi+-pi/3, n Z`

Explanation

Given,`Cos^2x = (√3 -√3sin x)^2`

=` 1 - sin^2x = 3 + 3sin^2x - 6sin x`

=` 4sin^2x - 6sin x+2 = 0 `

=`2sin^2x - 3sin x+1 = 0`

=`sin x = 1 or 0.5`

We know, `x = nπ + (-1)^nθ`

=` x = nπ + (-1)^n (π/2)`

or `x = nπ + (-1)^n (π/6)`

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