Let `P(n)` be the statement `7` divides `(2^(3n)-1)dot` What is `P(n+1)?`

Explanation

`P(n):2^(3n)−1`

If It's divisible by 7 then,


n=1 then,
`P(n):2^(3n)−1=2^(3×1)−1=7`

If n=k is true for some natural numbers, then It should also be true for (k+1),

For `n=k`
,
`P(k):2^(3k)−1=7d `

...