Using principle of mathematical induction prove that `cosalpha\ cos2alpha\ cos4alphacos(2^(n-1)alpha)=(sin2^nalpha)/(2^n sinalpha)` for all `n in Ndot`

Explanation

Let P(n) be the statement given by
`P(n):cosαcos2αcos4α......cos(2^(n−1)α)=(sin(2^nα)​)/(2^nsinα)`



StepI: ` P(1):cosα=(sin(2^1α)​)/(2^1sinα)`



`∵(sin(2^1α))/(2^1sinα)​`

...