Home
Class 11
MATHS
Let U1=1,\ U2=1\ a n d\ U(n+2)=U(n+1)+Un...

Let `U_1=1,\ U_2=1\ a n d\ U_(n+2)=U_(n+1)+U_nfor\ ngeq1.` use mathematical induction to show that: `U_n=1/(sqrt(5)){((1+sqrt(5))/2)^n-\ ((1-sqrt(5))/2)^n}\ for\ a l l\ ngeq1.`

Text Solution

Verified by Experts

We have to prove
`U_n=1/(sqrt(5)){((1+sqrt(5))/2)^n-\ ((1-sqrt(5))/2)^n}\ for\ a l l\ ngeq1.`

`U_1=1/(sqrt(5)){((1+sqrt(5))/2)^1-\ ((1-sqrt(5))/2)^1}\ for\ a l l\ ngeq1.`

`U_2=1/(sqrt(5)){((1+sqrt(5))/2)^2-\ ((1-sqrt(5))/2)^2}\ for\ a l l\ ngeq1.`

Hence (1) holds for n = 1 and n = 2 Now assume ...
Promotional Banner

Topper's Solved these Questions

  • LINEAR INEQUATIONS

    RD SHARMA|Exercise Solved Examples And Exercises|163 Videos
  • MATHEMATICAL REASONING

    RD SHARMA|Exercise Solved Examples And Exercises|181 Videos

Similar Questions

Explore conceptually related problems

Let U_(1)=1,U_(2)=1 and U_(n+2)=U_(n+1)+U_(n) for n>=1. Use mathematical induction to such that: :U_(n)=(1)/(sqrt(5)){((1+sqrt(5))/(2))^(n)-((1-sqrt(5))/(2))^(n)} for all n>1

Let u_(1)=1,u_2=2,u_(3)=(7)/(2)and u_(n+3)=3u_(n+2)-((3)/(2))u_(n+1)-u_(n) . Use the principle of mathematical induction to show that u_(n)=(1)/(3)[2^(n)+((1+sqrt(3))/(2))^n+((1-sqrt(3))/(2))^n]forall n ge 1 .

If a_(1)=1, a_(2)=5 and a_(n+2)=5a^(n+1)-6a_(n), n ge 1 . Show by using mathematical induction that a_(n)=3^(n)-2^(n)

Use mathematical induction to show that 1+3+5+…+ (2n-1) = n^(2) is true for a numbers n.

Let u_(n)=(1)/(sqrt((5)))[((1+sqrt(5))/(2))^(n)-((1-sqrt(5))/(2))^(n)] (0=0,1,2,3,……) , prove that u_(n+1)=u_(n)+u_(n-1)(n ge 1) .

If n is a positive interger,them (sqrt(5)+1)^(2n+1)-(sqrt(5)-1)^(2n-1) is

If a_1=1\ a n d\ a_(n+1)=(4+3a_n)/(3+2a_n),\ ngeq1\ a n d\ if\ (lim)_(n->oo)a_n=n then the value of a_n is sqrt(2) b. -sqrt(2) c. 2\ d. none of these

If U= [((1)/(sqrt2),(-1)/(sqrt2)),((1)/(sqrt2),(1)/(sqrt2))] , then U^(-1) is

int (du) / (u sqrt (u ^ (2) -1))

If U_(n)=2cos n theta, then U_(1)U_(n)-U_(n-1) is equal to -

RD SHARMA-MATHEMATICAL INDUCTION-Solved Examples And Exercises
  1. Prove by induction that 4+8+12++4n=2n(n+1) for all n Ndot

    Text Solution

    |

  2. Using principle of mathematical induction prove that cosalpha\ cos2a...

    Text Solution

    |

  3. Let U1=1,\ U2=1\ a n d\ U(n+2)=U(n+1)+Unfor\ ngeq1. use mathematical i...

    Text Solution

    |

  4. Prove the following by the principle of mathematical induction: 1+2...

    Text Solution

    |

  5. Prove the following by the principle of mathematical induction: 1^2...

    Text Solution

    |

  6. Prove the following by the principle of mathematical induction: 1+3...

    Text Solution

    |

  7. Using the principle of mathematical induction, prove that 1/(1*2)...

    Text Solution

    |

  8. Prove the following by the principle of mathematical induction: 1+3...

    Text Solution

    |

  9. Prove the following by the principle of mathematical induction:1/(2...

    Text Solution

    |

  10. Prove the following by the principle of mathematical induction: 1/(1...

    Text Solution

    |

  11. Prove the following by the principle of mathematical induction: 1/(...

    Text Solution

    |

  12. Prove the following by the principle of mathematical induction: 1/(...

    Text Solution

    |

  13. Prove the following by the principle of mathematical induction: \ 1...

    Text Solution

    |

  14. Prove the following by the principle of mathematical induction: 2+5...

    Text Solution

    |

  15. Prove the following by the principle of mathematical induction: \ 1....

    Text Solution

    |

  16. Prove the following by the principle of mathematical induction: \ 1...

    Text Solution

    |

  17. Prove the following by the principle of mathematical induction:1/2+...

    Text Solution

    |

  18. Prove the following by the principle of mathematical induction: \ 1...

    Text Solution

    |

  19. Prove the following by the principle of mathematical induction: a+(a...

    Text Solution

    |

  20. Prove the following by the principle of mathematical induction:\ 5^...

    Text Solution

    |