If `P(n):2xx4^(2n+1)+3^(3n+1)` is divisible by `lambda` for all `n in N` is true, then find the value of `lambda`.

Options

A. 9
B. 11
C. 13
D. 15

Answer

B

Explanation

If P(n) = 2 × 4^(2n + 1) + 3^(3n) + 1 is divisible by λ ∀ n ∈ N is true


for n = 1,

P(1):2*4^(2(1)+1)+3^(3(2)+1)

=2*4^3+3^4

=2*64+81

=128+81

P(1)=209
...