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If x^n-1 is divisible by x-lambda, then ...

If `x^n-1` is divisible by `x-lambda,` then the least prositive integral value of `lambda` is `1` b. `3` c. `4` d. `2`

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The correct answer is 1
Let P(n) :` x^n−1`is divisibleby (x−γ)
For n = `1. x^1−1 `is divisible by (x-γ).
Since, if x - 1 is divisible by x−γ.Then, the least possible integral value of γ is1 ...
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