Show that a real value of `x\ ` will satisfy the equation `(1-ix)/(1+ix)=a-i b\ if\ a^2+b^2=1` , when `a\ , b` are real.

Explanation

To show that a real value of \( x \) will satisfy the equation

\[ \frac{1 - ix}{1 + ix} = a - ib \]

given that \( a^2 + b^2 = 1 \), we will follow these steps:

...