Express the following complex numbers in the standard form `a+i b :(3-4i)/((4-2i)(1+i))`

Explanation

We have given: `impliesa + ib = (3 − 4 i)/ (( 4 − 2 i ) ( 1 + i ))`

=`( 3−4i)/((4−2i)(1+i))`

` a + ib = (3 − 4 i)/ ( 4 ( 1 + i ) − 2 i ( 1 + i )`

` a + ib = (3 − 4 i)/ ( 4 + 4i − 2 i -2i^2 )`

Since `i^2 = -1`

` a + ib =(3−4i)/(4+2i+2)`

` a + ib =(3−4i)/(6+2i)`

Now we multiplying and dividing with `6-2i`

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