Find the real values of `x\ a n d\ y ,\ if:(1+i)(x+i y)=2-5i`

Explanation

We have given,
`(1+i)(x+i y)=2-5i`

`1(x+i y)+i(x+iy)=2-5i`

`x+i y+ix+y(i^2)=2-5i`

Since` i^2` = -1

`x+i y+ix-y=2-5i`

`(x-y)+i(x+y)=2-5i`

Now on comparing real part and imaginary part in above eqution , we get

`(x-y)=2`and

...