Find the conjugates of the following complex number: `((3-2i)(2+3i))/((1+2i)(2-i))`

Explanation

We have given `((3-2i)(2+3i))/((1+2i)(2-i))`

we have to find the conjugate of
`((3-2i)(2+3i))/((1+2i)(2-i))`

then

Let a+ib=`((3-2i)(2+3i))/((1+2i)(2-i))`

a+ib=`(3(2+3i)-2i(2+3i))/(1(2-i)+2i(2-i))`

a+ib=`(6+9i-4i-6(i^2))/(2-i+4i-2(i^2))`

Since `(i^2)=-1`

...