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If a=costheta+isintheta, then (1+a)/(1-a...

If `a=costheta+isintheta,` then `(1+a)/(1-a) ` is
a. `cot(theta/2)`
b. `cottheta`
c. `icot(theta/2)`
d. `itan(theta/2)`

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To solve the problem, we need to simplify the expression \((1 + a)/(1 - a)\) where \(a = \cos \theta + i \sin \theta\). ### Step-by-step Solution: 1. **Substitute \(a\)**: \[ a = \cos \theta + i \sin \theta \] ...
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