How may litres of water will have to be added to `1125` litres of the `45 %` solution of acid so that the resulting mixture will contain more than `25 %` but less than `30%` acid content?

Explanation

Let the quantity of water to be added to solution `=x` liters

`therefore 25 %(1125+x)<45 %` of 1125

`Rightarrow 25/100(1125+x)<45/100 times 1125`

`Rightarrow 1125+x<45/100 times 1125`

`Rightarrow 1125+x<45 times 45`

`Rightarrow 1125+x<2025`

`Rightarrow x<2025-1125`

`Rightarrow x<900`


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