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Find\ x in each of the following: x/(10 ...

Find`\ x` in each of the following: `x/(10 !)=1/(8!)+1/(9!)`

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Given
`x/(10 !)=1/(8!)+1/(9!)`
On multiplying both sides by `10 !` both side, we get
`x=(10!)/(8!)+(10!)/(9!)`
=` x =(10xx9xx(8!))/(8!)+(10xx(9!))/(9!)`
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RD SHARMA-PERMUTATIONS-Solved Examples And Exercises
  1. Prove that: 1/(9!)+1/(10 !)+1/(11 !)=(122)/(11 !)

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  2. Find\ x in each of the following: 1/(4!)+1/(5!)=x/(6!)

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  3. Find\ x in each of the following: x/(10 !)=1/(8!)+1/(9!)

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  4. Find\ x in each of the following: 1/(6!)+1/(7!)=x/(8!)

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  5. Convert the following products into factorial: 5. 6. 7. 8. 9. 10

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  6. Convert the following products into factorial: 3.6.9.1.15.18

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  7. Convert the following products into factorial: (n+1)(n+2)(n+3).......(...

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  8. Convert the following products into factorial: 1. 3. 5. 7. 9 (2n-1)

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  9. Which of the following are true: (2+3)!=2!+3!

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  10. Which of the following are true: \ (2xx3)!=2!xx3!

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  11. Prove that: n !(n+2)=n !+(n+1)!

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  12. if(n+2)! =60[(n-1)!],find n

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  13. If (n+1)! =90[(n-1)!], fin d n

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  14. If (n+3)! =56[(n+1)! fin n

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  15. Prove that ((2n)!)/(n !)=2^n{1. 3. 5 (2n-1)}

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  18. Find the number of 4 letter words, with or without meaning which can b...

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