How many different numbers of six digits can be formed from the digits `3,1,7,0,9,5` when repetition o digits is not allowed?

Explanation

If the number is to be divisible by 10, then unit place must be 0.



We are provided with 6 digits `0,1,3,5,7` and `9`


Since, unit place digit is 0 and its position is fixed, the remaining number of digits can be arranged in `5!` ways.


Therefore, required number of digits =`5_(P_4)=120`