How many numbers of six digits can be formed from the digits `0,1,3,5,7` and 9 when no digit is repeated? How many of them are divisible by `10`?

Explanation

If the number is to be divisible by 10, then unit place must be 0.



We are provided with 6 digits `0,1,3,5,7` and `9` and since we have to form a 6 digit number with no digit repeated, we will have to use all the digits.


Since, unit place digit is 0 and its position is fixed, the remaining number of digits can be arranged in `5!` ways.


Therefore, required number of digits =`5! =120`