In how many ways can five children stand in a queue?

Explanation

Number of arrangements of ‘n’ things taken all at a time = `/^(n)P_n`


so,The total number of ways in which five children can stand in a queue = the number of arrangements of ` 5 `things taken all at a time = P `(5, 5`)



So,


`P (5, 5) = (5!)/((5 – 5)!)`

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