How many numbers greater than a million casn be formed with the digits 2,3,0,3,4,2,3?

Explanation

Any number of greater than a million will contain all the seven digits.


Now, we have to arrange these seven digits, out of which `2` occurs twice, `3` occurs twice and the rest are distinct.


The number of such arrangements =`(7!)/(2!×3!)=420`


These arrangements also include those numbers which contain `0` at the million’s place.


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