In how many ways can 5 boys and 3 girls be seated in a row so that each girl is between 2 boys?

Explanation

Since, the boys and girls are alternating.

5 boys can be arranged in 5 places in `(5!+5!)` ways and 3 girls can be arranged in 3 places in `(3!+3!)` ways.

Hence, the total number of ways

`= (5!+5!)×(3!+3!)`

`= 2×(5!)×2×(3!)`

`= 4×[5×4×3×2]×[3×2]`

`= 4×120×6`

`= 4×720`
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