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Evaluate the following: \ ^(n+1)Cn...

Evaluate the following: `\ ^(n+1)C_n`

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`n+1 C_{n}=\ ^{n+1} C_{1} quad[because\ ^{n} C_{r}=\ ^{n} C_{n-r}]`
`Rightarrow\ ^{n+1} C_{n}=\ ^{n+1} C_{1}=frac{n+1}{1} times\ ^{n} C_{0}`
`Rightarrow\ ^{n+1} C_{n}=n+1 quad[because\ ^{n} C_{0}=1]`
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