In how many ways can a team of 3 boys and 3 girls be selected from 5 boys and 4 girls?

Explanation

A team of 3 boys and 3 girls is to be selected from 5 boys and 4 girls.


3 boys can be selected from 5 boys in `5_(C_3)` ways.


3 girls can be selected from 4 girls in `4_(C_3)` ways.


Therefore, by multiplication principle, number of ways in which a team of 3 boys and 3 girls can be selected


`=>5_(C_3)**4_(C_3)`

`=>(5!)/(3!2!)**(4!)/(3!1!)`

`=>(5**2)**4`

`=>40`