If `C(n , 12)=C(n ,8),\ t h e n\ C(22 , n)` is equal to a. 231 b. 210 c. 252 d. 303

Explanation

Given `n_(C_12)=n_(C_8)`

As we known the identity

if `n_(C_a)=n_(C_b)`

then `n=a+b`

`=>n=12+8`

`n=20`

Then the value of `22_(C_20)`

`=>(22!)/(20!**2!)`

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