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If \ ^ C1=\ \ ^n 2 then 2m=n m=(n-1) d. ...

If `\ ^ C_1=\ \ ^n 2` then `2m=n` m=(n-1)` d. `2n=m(m-1)`

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Knowledge Check

  • If m, n, r are positive integers such that r lt m , n then ""^(m)C_(r )+""^(m)C_(r-1)" "^(n)C_(1)+""^(m)C_(r -2)" "^(n)C_(2)+ … +""^(m)C_(1)" "^(n)C_(r-1) +""^(n)C_(r ) equals

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    B
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  • If f(x) = log ((m(x))/(n(x))), m(1) = n(1) = 1 and m'(1) = n'(1) = 2, " then" f'(1) is equal to

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